- Author:
- sleepycal
- Posted:
- September 12, 2010
- Language:
- Python
- Version:
- 1.2
- Score:
- 1 (after 1 ratings)
ReportBug() allows you to send exception details to you, via email, but with far more detail than the default. It uses the base function for the traceback used by the Debug mode on Django.
This is a first revision, so the emails have no decent styling, but it works, and shows scope on each stack.
It will automatically generate a random serial number per error, so you can track them in your favourite bug tracker. It also has support for you to pass it a request variable, so the mail would also contain request/response context. Again, i'm gonna look into doing this manually in the future.
Hope this helps!
Mwah.
Cal Leeming.
cal [at] simplicitymedialtd.co.uk.
Simplicity Media Ltd.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 | """
_FROM / _TO will define the email delivery settings.
Code can be easily adapted to use the values from settings.py.
The next revision will include this
"""
_FROM = 'My Errors <[email protected]>'
_TO = '[email protected]'
"""
ReportBug() allows you to send exception details to you, via email, but with
far more detail than the default. It uses the base function for the traceback
used by the Debug mode on Django.
This is a first revision, so the emails have no decent styling, but it works,
and shows scope on each stack.
It will automatically generate a random serial number per error, so you can track them
in your favourite bug tracker. It also has support for you to pass it a request variable,
so the mail would also contain request/response context. Again, i'm gonna look into doing
this manually in the future.
Hope this helps!
Mwah.
Cal Leeming
cal [at] simplicitymedialtd.co.uk
Simplicity Media Ltd
"""
try:
lol = 4
raise Exception, "test"
except:
ReportBug()
raise
def ReportBug(request=None, serno=None):
try:
import sys
import traceback
import os
# Mail the admins with the error
exc_info = sys.exc_info()
if exc_info:
_file, _line, _func, _line = traceback.extract_tb(exc_info[2])[0]
_file = os.path.basename(_file)
else:
_file, _line, _func, _line = (None, None, None, None)
# Check if we have a serno
if not serno:
from hashlib import md5
import random
serno = md5()
serno.update(str(random.random()))
serno = serno.hexdigest()
# When DEBUG is False, send an error message to the admins.
subject = 'Exception in %s (line %s) (ID: %s)' % (
_file,
_line,
serno
)
message = 'Traceback:\n%s\n\n' % ('\n'.join(traceback.format_exception(*exc_info)),)
import sys
from django.views.debug import ExceptionReporter
from django.http import HttpRequest
from django.conf import settings
from django.core.mail import EmailMultiAlternatives
if not request:
h = HttpRequest()
h.META['SERVER_NAME'] = 'FAKE'
h.META['SERVER_PORT'] = '80'
else:
h = request
exp = sys.exc_info()
t = ExceptionReporter(h, *exp)
subject, from_email, to = '[Django] %s'%(str(exp[1])), _FROM, _TO
text_content = message
html_content = t.get_traceback_html()
msg = EmailMultiAlternatives(subject, text_content, from_email, [to])
msg.attach_alternative(html_content, "text/html")
msg.send()
except Exception, e:
mail_admins("SERIOUS ERROR", "Not sure what happened.. %s"%str(e), fail_silently=True)
|
More like this
- Template tag - list punctuation for a list of items by shapiromatron 10 months, 3 weeks ago
- JSONRequestMiddleware adds a .json() method to your HttpRequests by cdcarter 11 months ago
- Serializer factory with Django Rest Framework by julio 1 year, 5 months ago
- Image compression before saving the new model / work with JPG, PNG by Schleidens 1 year, 6 months ago
- Help text hyperlinks by sa2812 1 year, 7 months ago
Comments
why not use uuid for really good serial number?
#
Please login first before commenting.