Simple code , judge login require by url
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 | from django.conf.urls.defaults import patterns,url
#or use login_required
from django.contrib.admin.views.decorators import staff_member_required
def login_url(regex, view, *p,**args):
"""
urlpatterns = patterns('',
login_url(r'^$',direct_to_template, {'template': '1.html'}),
)
"""
return url(regex,staff_member_required(view),*p,**args)
def login_patterns(*p):
"""
urlpatterns = login_patterns('',
(r'^$',direct_to_template,{'template':'1.html'}),
)
"""
d=[]
d.append(p[0])
for i in xrange(1,len(p)):
d.append(login_url(*p[i]))
return patterns(*d)
|
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