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Tag "json"

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Modelaware json serializer

A serializer that handles dicts with querysets and model instances, nice to use if you have a paginator context. paginate_by = 8 paginator = ObjectPaginator(queryset, paginate_by) page = request.GET.get('page', 1) try: page = int(page) object_list = paginator.get_page(page - 1) except (InvalidPage, ValueError): if page == 1 and allow_empty: object_list = [] else: raise Http404 result = { 'object_list' : object_list, 'is_paginated': paginator.pages > 1, 'results_per_page': paginate_by, 'has_next': paginator.has_next_page(page - 1), 'has_previous': paginator.has_previous_page(page - 1), 'page': page, 'next': page + 1, 'previous': page - 1, 'pages': paginator.pages, 'hits' : paginator.hits, } serialize(result, ensure_ascii=False)

  • json
  • serialization
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Format transition middleware

Note: This is a testing middleware. This snippets may be changed frequently later. What's it ----------- Sometimes I thought thow to easy the output data into another format, except html format. One way, you can use decorator, just like: @render_template(template='xxx') def viewfunc(request,...): And the output data of viewfunc should be pure data. And if want to output json format, you should change the decorator to: @json_response def viewfunc(request,...): I think it's not difficult. But if we can make it easier? Of cause, using middleware. So you can see the code of `process_response`, it'll judge the response object first, if it's an instance of HttpResponse, then directly return it. If it's not, then get the format of requst, if it's `json` format, then use json_response() to render the result. How to setup `request.format`? In `process_request` you and see, if the `request.REQUEST` has a `format` (you can setup it in settings.py with FORMAT_STRING option), then the `request.format` will be set as it. If there is not a such key, then the default will be `json`. So in your view code, you can just return a python variable, this middleware will automatically render this python variable into json format data and return. For 0.2 it support xml-rpc. But it's very different from common implementation. For server url, you just need put the same url as the normal url, for example: http://localhost:8000/booklist/ajax_list/?format=xmlrpc Notice that the format is 'xmlrpc'. A text client program is: from xmlrpclib import ServerProxy server = ServerProxy("http://localhost:8000/booklist/ajax_list/?format=xmlrpc", verbose=True) print server.booklist({'name':'limodou'}) And the method 'booklist' of server is useless, because the url has include the really view function, so you can use any name after `server`. And for parameters of the method, you should use a dict, and this dict will automatically convert into request.POST item. For above example, `{'name':'limodou'}`, you can visit it via `request.POST['name']` . For `html` format, you can register a `format_processor` callable object in `request` object. And middleware will use this callable object if the format is `html`. Intall --------- Because the view function may return non-HttpResponse object, so this middleware should be installed at the end of MIDDLEWARE_CLASSES sections, so that the `process_response` of this middleware can be invoked at the first time before others middlewares. And I also think this mechanism can be extended later, for example support xml-rpc, template render later, etc, but I have not implemented them, just a thought. Options --------- FORMAT_STRING used for specify the key name of format variable pair in QUERY_STRING or POST data, if you don't set it in settings.py, default is 'format'. DEFAYLT_FORMAT used for default format, if you don't set it in settings.py, default is 'json'. Reference ----------- Snippets 8 [ajax protocol for data](http://www.djangosnippets.org/snippets/8/) for json_response

  • middleware
  • format
  • json
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62 snippets posted so far.